BUG: Select Case Does Not Allow Character Expression StringLast reviewed: July 12, 1995Article ID: Q123662 |
The information in this article applies to:
SYMPTOMSCompiling a program that contains a SELECT CASE statement that uses a variable in a character substring of length 1, fails and gives the following error message:
F2868: SELECT CASE : character expression must be of length 1 CAUSEThe compiler incorrectly evaluates the length of a character substring, when the character substring is defined using a variable, not a constant.
RESOLUTIONAvoid a SELECT statement that uses a character substring defined with a variable. Instead, use a character substring defined with a constant. As an alternative, you can define a temporary character variable of length 1 and assign the substring to that variable, which can be later used with a SELECT statement.
STATUSMicrosoft has confirmed this to be a bug in the Microsoft products listed at the beginning of this article. We are researching this problem and will post new information here in the Microsoft Knowledge Base as it becomes available.
MORE INFORMATION
Sample Code to Reproduce ProblemC Compile options needed: none C The following program reproduces the problem:
program go character*5 a integer*4 len a = "Hello" len = 1 select case( a(len:len) ) ! offending statement case default end select end Sample Code to Solve ProblemC Compile options needed: none C The following code solves the problem:
program go character*5 a a = "Hello" select case( a(1:1) ) case default end select end Sample Code to Solve ProblemC Compile options needed: none C The following code solves the problem:
program go character a*5,tmp*1 integer*4 len a = "Hello" len = 1 tmp=a(len:len) select case( tmp ) case default end select end |
Additional reference words: 1.00 1.00a
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