How to Create a "Windows-type" Incremental Search Box in VFPLast reviewed: May 16, 1996Article ID: Q150753 |
The information in this article applies to:
SUMMARYAlthough the default List Box control has basic incremental search capabilities, the list box must have focus for the function to work. Its functionality differs from the implementation found in other Windows applications, such as the Search option of Help, where the string to be searched for is entered into a text box above a list box that displays the first matching item as each character is entered. This article describes how to create a technique that allows a list box to searched incrementally, regardless of its RowSource type.
MORE INFORMATION
NOTE: Performance is effected by the number of records and the position of the item to be found within the list. Performance is improved by dividing the list into portions and substituting variables in the FOR statement which lowers the number of items to compare the text string with. In this example, the list is divided into quarters:
LOCAL cVal, cLen, c1st, c2nd, c3rd, n1st, n2nd, n3rd, nTop, nEnd, ;
nMax, oList
oList = Thisform.List1
* 1st = 1 to n2nd-1
nMax = oList.ListCount
n1st = INT( nMax * .25 ) && 1st quarter
n2nd = INT( nMax * .50 ) && 2nd quarter
n3rd = INT( nMax * .75 ) && 3rd quarter
c1st = UPPER( oList.ListItem[ n1st ] ) && avoids case sensitivity
c2nd = UPPER( oList.ListItem[ n2nd ] ) && when list contains
c3rd = UPPER( oList.ListItem[ n3rd ] ) && mixed case entries
cVal = ALLTRIM( UPPER( this.Value ) ) && first character caps
cLen = LEN( cVal )
DO CASE
CASE cVal <= LEFT( c1st, cLen )
nTop = 1
nEnd = n1st
CASE cVal <= LEFT( c2nd, cLen )
nTop = n1st + 1
nEnd = n2nd
CASE cVal <= LEFT( c3rd, cLen )
nTop = n2nd + 1
nEnd = n3rd
OTHERWISE
nTop = n3rd + 1
nEnd = nMax
ENDCASE
FOR nIndex = nTop TO nEnd && loop through each item within range
IF UPPER( oList.ListItem[ nIndex ] ) = cVal
oList.ListIndex = nIndex && select this item if matched
EXIT && drop out of loop
ENDIF
ENDFOR
oList.Refresh && update the display to show selected item
If the list is extensive and requires a large number of divisions, create
an array as a property of the form, and assign the character and numeric
division boundaries once in the Init event of the form instead of each time
in the InteractiveChange event of the form. In the following example, the
list is divided into sections:
Create the following two new Form properties: cLimit[9] and nLimit[9]
In the Init event of the form, enter:
LOCAL nDx, nMax
oLst = this.List1 && object reference to this form''''''''s list box
nMax = oLst.ListCount && divide into tenths
FOR nDx = 1 TO 9
* assign number at each tenth boundary (used as index into list)
this.nLimit[ nDx ] = INT( nMax * ( .10 * nDx ) )
* assign list item found at this position in the list
this.cLimit[ nDx ] = UPPER( oLst.ListItem[ this.nLimit[ nDx ] ] )
ENDFOR
In the InteractiveChange event of the text box, enter:
LOCAL cVal, cLen, nTop, nEnd, nIdx, nDex, oLst
oLst = thisform.list1
cVal = ALLTRIM( UPPER( this.Value ) )
cLen = LEN( cVal )
* if not found in the sections checked, default to the last section
nTop = thisform.nLimit[ 9 ] + 1 && i.e., one past the end of the 9th
nEnd = oLst.ListCount && section to the end of the list
IF cVal <= LEFT( thisform.cLimit[ 1 ], cLen ) && compare to 1st element
nTop = 1
nEnd = thisform.nLimit[1]
ELSE
FOR nIdx = 2 TO 9 && loop through the remaining section limits
IF cVal <= LEFT( thisform.cLimit[ nIdx ], cLen )
nTop = thisform.nLimit[ nIdx - 1 ] + 1 && previous end plus 1
nEnd = thisform.nLimit[ nIdx ] && limit of current section
EXIT && drop out of loop since section is found
ENDIF
ENDFOR
ENDIF
* the remaining code is the same structure as in the previous example
FOR nDex = nTop TO nEnd && loop through each item with range
IF UPPER( oLst.ListItem[ nDex ] ) = cVal
oLst.ListIndex = nDex
EXIT
ENDIF
ENDFOR
oLst.Refresh
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Additional reference words: 3.00 3.00b VFoxWin
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