XL: Conversion to Base x Function Not AvailableLast reviewed: February 3, 1998Article ID: Q140035 |
The information in this article applies to:
SYMPTOMSMicrosoft Excel version 4.0 includes an add-in function named BASE() which accepts input for a base 10 number and a number designating the base to which it should be converted. BASE() outputs a text string representation of the number in that base. For example, BASE() converts the number 5 in base 10 to the string 101 if base 2 is requested. Microsoft Excel versions 5.0 and later do not include the BASE() function. When you open a workbook in Microsoft Excel version 5.0 or later, you receive a "#NAME" error in the cells that contain the BASE() function.
STATUSThis behavior is by design of Microsoft Excel versions 5.0 and later.
MORE INFORMATIONMicrosoft provides programming examples for illustration only, without warranty either expressed or implied, including, but not limited to, the implied warranties of merchantability and/or fitness for a particular purpose. This article assumes that you are familiar with the programming language being demonstrated and the tools used to create and debug procedures. Microsoft support engineers can help explain the functionality of a particular procedure, but they will not modify these examples to provide added functionality or construct procedures to meet your specific needs. If you have limited programming experience, you may want to contact the Microsoft fee-based consulting line at (800) 936-5200. For more information about the support options available from Microsoft, please see the following page on the World Wide Web:
http://www.microsoft.com/support/supportnet/refguide/default.aspThe following sample Microsoft Visual Basic for Applications function is a simple base function similar to the Microsoft Excel 4.0 BASE() function. This example does not perform any decimal conversion.
Sample Visual Basic Procedure
Function Base(InValue As Double, NewBase As Double) As String Dim TestVal As Double, counter As Integer, Alpha As String Dim Holder As Integer Application.Volatile On Error GoTo FixError If InValue = 0 Then GoTo FixError If NewBase = 0 Then GoTo FixError counter = 0 TestVal = 0 While TestVal < InValue TestVal = NewBase ^ counter If TestVal < InValue Then counter = counter + 1 Wend counter = counter - 1 Alpha = "" Holder = 0 For x = counter To 0 Step -1 Holder = Int(InValue / (NewBase ^ x)) Alpha = Alpha & Application.Text(Holder, "0") InValue = InValue - (Holder * (NewBase ^ x)) Next x Base = Alpha Exit Function FixError: Base = "#Value" End Function |
Additional query words: 5.00 5.00a 5.00c 7.00 7.00a XL98 XL97 XL7 XL5
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