PRB: Unexpected C2440 Error in C++ TypecastLast reviewed: August 7, 1997Article ID: Q104243 |
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MS-DOS | WINDOWS | WINDOWS NTkbtool kbprb The information in this article applies to:
SYMPTOMSThe following error
Error C2440 : 'Conversion': cannot convert from 'type1' to 'type2'is generated when a statement of the form
TYPE ( identifier ) ( expression );is used to type cast a function pointer and make a call simultaneously.
CAUSEThis is expected C++ compiler behavior. The sample code below explains the problem in a more understandable way. If the following three statements taken from the sample code are compiled
typedef void (* funcptr) (int); ... void f(int){...}; ... funcptr (f)(1); // Error C2440 ...the following error message is generated:
error C2440: 'initializing' : cannot convert from 'const int' to 'void (__cdecl *) (int)'Although the last statement appears to be typecasting the function "f" to funcptr, the compiler thinks it is declaring an object of name "f" of type funcptr and initializing it with the integer constant "1" equivalent to having
funcptr f = 1; or void (*f) (int) = 1;which makes the error message much more understandable.
RESOLUTIONThe way to the achieve the desired typecast is to add another set of parenthesis, for example
((funcptr)f)(1);which resolves the confusion for the compiler, which thus treats the typecast in the way it should. NOTE: Using a C++ style cast, such as (funcptr(f))(1), produces a syntax error. You must use C-style casting. Another method is to have a pointer explicitly bind a new name to the function, for example
void (*f1)(int) = f;and use:
f1(1); // OK MORE INFORMATIONThe sample below demonstrates the error and workarounds.
Sample Codetypedef void (*funcptr) (int);
void f(int); void main(){ ((void (*) (int)) f)(1); funcptr (f) (1); // Gives error C2440 ((funcptr)f)(1); void (*f1) (int) = f; f1(1);}
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