FIX: printf Does Not Recognize "\n\r" when Using Conversion

WINDOWS   | WINDOWS NT

The information in this article applies to:

• The C Run-time (CRT), included with:

      - Microsoft Visual C++ for Windows, versions 1.0 and 1.5
      - Microsoft Visual C++ 32-bit Edition, version 1.0
  

SYMPTOMS

If an explicit type-conversion syntax is used for the return value of printf(), printf() does not recognize the escape sequence \n\r in its format string.

The following macro prints "<string x>\n\r":

   #define PRINT(x) void( printf("%s\n\r", x ) )

RESOLUTION

To correct the error, use one of the following workarounds:

1. Use ASCII values for the line feed and carriage return. For example:

         #define PRINT(x)  void( printf("%s%c%c",x,10,13 ) )
   

   -or-

2. Use explicit typecasting instead. For example:

         #define PRINT(x)  (void)( printf("%s\n\r",x ) )
   

   -or-

3. Program without the conversion or casting if possible. For example:

         #define PRINT(x)  printf("%s\n\r", x )
   

STATUS

Microsoft has confirmed this to be a bug in the products listed at the beginning of this article. This problem was corrected in Visual C++ 32-bit Edition, version 2.0.