HOWTO: Convert 10-Byte Long Doubles to 8-Byte DoublesLast reviewed: October 3, 1997Article ID: Q129209 |
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SUMMARYWith the 16-bit Microsoft C/C++ compilers, long doubles are stored as 80- bit (10-byte) data types. Under Windows NT, in order to be compatible with other non-Intel floating point implementations, the 80-bit long double format is aliased to the 64-bit (8-byte) double format. This means that 32-bit programs may not be able read back data files written by 16-bit programs because the long double formats are incompatible. On Intel platforms, the only workaround is to let the floating point processor handle the conversion from 80-bit to 64-bit doubles. Afterwards, the data can be stored back into a 64-bit double for use under Win32. The sample code below illustrates how you could use floating point instructions in inline assembly to convert from a 10-byte double in a data file to an 8-byte double.
Sample Code
/* Compile options needed: none */ #include <stdio.h> void main(void) { FILE *inFile; char buffer[10]; long double Newdbl; inFile = fopen("data","rb"); fread(buffer, 10, 1, inFile); // reads in 10-byte long double fclose(inFile); // This moves the contents of the buffer into the floating point // register, which then then takes care of the automatic convertion // back to a 8-byte long double _asm { fld TBYTE PTR buffer; fstp Newdbl; } } |
Additional query words: 8.00 9.00 9.10
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