printf() Default Floating-Point Precision Is 6 Decimals

Last reviewed: January 18, 1996
Article ID: Q29557

The information in this article applies to:

  • The C Run-time (CRT), included with:

        - Microsoft C for MS-DOS, versions 5.0, 5.1, 6.0, 6.0a, and 6.0ax
        - Microsoft C for OS/2, versions 5.1, 6.0, and 6.0a
        - Microsoft C/C++ for MS-DOS, version 7.0
        - Microsoft Visual C++ for Windows, versions 1.0 and 1.5
        - Microsoft Visual C++ 32-bit Edition, versions 1.0, 2.0 and 4.0
    

SUMMARY

By default, the printf() function displays a floating-point number to six digits of precision. This default also holds for double precision numbers.

To display additional digits of precision, specify a value for the precision field in the printf() format specification, as follows:

   %[<flags>][<width>][.<precision>]<type>

MORE INFORMATION

The code example below demonstrates documented printf() behavior that may appear to be a problem with the function.

   #include <stdio.h>

   main()
   {
      double d = 1.2345678912;

      printf("%e\n", d);
      printf("%le\n", d);
   }

This code example produces the following output:

   1.234568e+000
   1.234568e+000

To display the value d to its full precision, modify the code example to use the following statement:

   printf("%.15le", d);


Additional reference words: kbinf 1.00 1.50 2.00 5.10 6.00 6.00a 6.00ax
7.00
KBCategory: kbprg kbfasttip
KBSubcategory: CRTIss


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Last reviewed: January 18, 1996
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