PRB: printf() Appears to Print Incorrect Results for FloatsLast reviewed: July 24, 1997Article ID: Q44816 |
The information in this article applies to:
SYMPTOMSThe printf() in the sample code below does not print out the correct values; the float is printed with a hexadecimal specifier before the float specifier.
CAUSEThe problem is that a 2-byte format specifier is being used for an 8-byte value.
RESOLUTIONTo correct this problem, replace "%x" and "%lx" with "%lx %lx".
MORE INFORMATION
Sample Code
/* Compile options needed: none */ #include <stdio.h> main() { float flt = 1.701411e+038; double dbl = 1.701411e+038; printf("\nFLOAT %x %e", flt,flt); printf("\nDOUBLE %lx %le",dbl,dbl); }The above code produces incorrect output. However, the source code is incorrect. When printing, the above code is using a 2-byte hex format specifier %x or a 4-byte hex format specifier %lx with an 8-byte double argument (the float is also passed as a double). This produces the incorrect results. To solve this problem, use two %lx format specifiers to remove 8-bytes off the stack before printing the second double. For example:
printf("\nFloat %lx %lx %e",flt,flt); printf("\nDouble %lx %lx %le",dbl,dbl);This works correctly for Microsoft C under MS-DOS or OS/2; however, this code may not be portable under other systems that support types of different sizes. Eight bytes are passed, independent of the fact that one argument is a float and the other a double, because the float is being promoted to a double. This is because all floats are passed as doubles unless they are specified as floats in the prototype. Because printf() has a variable number of parameters, the arguments are not prototyped and therefore all floats are promoted up to doubles. |
Keywords : CRTIss
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