INFO: Initializing Bitfields as Integers in CLast reviewed: September 4, 1997Article ID: Q60252 |
The information in this article applies to:
SUMMARYIn Microsoft C, you can initialize the values of an entire bitfield structure as an integer in several ways:
MORE INFORMATIONIn Microsoft C, bitfields are stored in word-sized blocks with the least significant bit representing the first bit of the bitfield. For example, the bitfields in bitstruct, defined below in the example, are stored as follows:
< p4 > < p3 > < p2> <p1> |?|?|?|?|?|?|?|?|?|?|?|?|?|?|?|?|Assigning the integer 0x4c to this structure results in the following bit pattern:
|0|0|0|0|0|0|0|0|0|1|0|0|1|1|0|0|The bitfields are given the following respective values:
p1=0 p2=3 p3=2 p4=0If the number of bits needed for a bitfield structure exceeds 16 in code compiled for MS-DOS or Windows, words will be added as needed to provide room for the structure with no single bitfield crossing a word boundary. Microsoft C/C++, 32-bit Edition, stores bitfield structures in double word values. If the field requires more than 32 bits, the compiler uses additional double words as needed. NOTE: There is no "standard" for storing bitfields in memory; therefore, any program that depends on a particular storage method is not portable to systems that use a different method.
Sample Code
struct strtype { unsigned p1:2; unsigned p2:3; unsigned p3:5; unsigned p4:5; } bitstruct; union untype { struct strtype un_bitstruct; unsigned bit_integer; } bitunion; unsigned *intptr; unsigned intgr; void main(void) { /* Using the bitfield structure only */ /* Set the pointer to address of bitfield */ intptr = (unsigned *)&bitstruct; /* Change the bitfield */ *intptr = 0x4c; /* Get the new value */ intgr = *(unsigned *)&bitstruct; /* Using an union makes this much easier (syntactically) */ /* Set the pointer */ intptr = &bitunion.bit_integer; /* Change the bitfield */ bitunion.bit_integer = 0x4c; /* Get the new value */ intgr = bitunion.bit_integer; } |
Additional query words: 8.00 8.00c 9.00
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