INFO: strtok() Needs No Additional Space to Insert Nulls

Last reviewed: September 4, 1997
Article ID: Q71285

The information in this article applies to:
  • The C Run-time (CRT) included with: - Microsoft C for MS-DOS, versions 5.1, 6.0, 6.0a, 6.0ax - Microsoft C for OS/2, versions 5.1, 6.0, 6.0a - Microsoft C/C++ for MS-DOS, version 7.0 - Microsoft Visual C++ for Windows, versions 1.0, 1.5 - Microsoft Visual C++ 32-bit Edition, versions 1.0, 2.0, 4.0, 5.0

SUMMARY

Sometimes it is mistakenly assumed that when the C strtok() function inserts a null character ('\0') into the source string at the end of a token, the length of the source string increases by this new character. This is not the case because an additional character is not actually being inserted. Instead, the delimiter that strtok() found to indicate the end of the token is replaced by the null character.

Thus, when declaring or allocating the string of tokens, you do not need to make allowances for the null characters to be inserted.

Keywords          : CRTIss kbfasttip
Version           : MS-DOS:5.1,6.0,6.00a,6.00ax,7.0; OS/2:5.1,6.0,6.00a;  WINDOWS:1.0,1.5; WINDOWS NT:1.0,2.0,4.0,5.0
Platform          : MS-DOS NT OS/2 WINDOWS


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Last reviewed: September 4, 1997
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