Extending a Common Block with an EQUIVALENCE Statement
ID: Q67229
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The information in this article applies to:
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Microsoft FORTRAN for MS-DOS, versions 4.0, 4.01, 4.1, 5.0, 5.1
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Microsoft FORTRAN for OS/2, versions 4.1, 5.0, 5.1
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Microsoft FORTRAN PowerStation for MS-DOS, versions 1.0, 1.0a
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Microsoft Fortran Powerstation 32 for Windows NT, versions 1.0, 4.0
SUMMARY
An EQUIVALENCE statement can be used to extend a common block size by
EQUIVALENCing the last element of a common block with the first element
of an array that is not in a common block. This is demonstrated
in the code below.
This article expands upon the information in the EQUIVALENCE statement
section of the "Microsoft FORTRAN Reference" manual, which discusses
extending common blocks found.
MORE INFORMATION
The following code fragment shows a common block being extended from
4 bytes to 800 bytes in length.
C ***** FORTRAN program fragment *****
REAL*4 VAR, A(200)
COMMON /TEST/ VAR
EQUIVALENCE (VAR, A(1))
In this fragment, the common block TEST is initially 4 bytes in
length. The equivalence statement specifies that VAR and A(1) will
share the same location in memory. Because all of A's elements are
contiguous in memory, the common block TEST is extended to be 200 x 4
or 800 bytes in length. This is shown graphically below:
|01|02|03|04|05|06|07|08|09|0A|0B|0C|0D|0E|0F|10|
|------------------------------------------------
|....VAR....|
|------------------------------------------------
|....A(1)...|....A(2)...|....A(3)...|....A(4)...|
|------------------------------------------------
|<-- Beginning address of common block TEST
The guidelines listed below must be followed when using EQUIVALENCE to
extend a common block's length:
- A common block may only be extended by adding elements to the end
of the common block. An EQUIVALENCE operation cannot add elements
that precede the common block as in the following example:
C ***** FORTRAN program fragment *****
REAL*4 VAR, A(200)
COMMON /TEST/ VAR
EQUIVALENCE (VAR, A(2))
Here VAR and A(2) will share the same memory location. Because A(1)
precedes A(2) in memory, it will also precede VAR, which is the
beginning of the common block. This is called extending a common
block forward and is shown graphically below:
|??|??|??|??|01|02|03|04|05|06|07|08|09|0A|0B|0C|0D|0E|0F|10
------------|------------------------------------------------
............|....VAR....|
------------|------------------------------------------------
|....A(1)...|....A(2)...|....A(3)...|....A(4)...|....A(5)...
------------|------------------------------------------------
............|<-- Beginning address of common block TEST
The following error is generated when the code listed above is
compiled:
F2320: A : EQUIVALENCE : extends common block TEST forward
- The ANSI FORTRAN 77 Standard states that a NAMED common block must
be of the same size in all program units of an executable program
in which it appears. For this reason, when a NAMED common block is
extended, every subsequent subprogram accessing the common block
must declare it according to its new size. For example, in the
code below, a NAMED common block is again declared with one REAL*4
element and then EQUIVALENCEd with a 200 element REAL*4 array. In
the subroutine, the common block is then declared with its new size
of 200 elements:
C ***** FORTRAN program fragment *****
PROGRAM main
REAL*4 VAR, A(200)
COMMON /TEST/ VAR
EQUIVALENCE (VAR, A(1))
CALL sub()
.
.
END
SUBROUTINE sub ()
REAL*4 B
COMMON /TEST/ B(200)
.
.
RETURN
END
However, FORTRAN 5.0 will allow a NAMED common block to have
different sizes in subprogram units. In this situation, the compiler
generates the following warning:
F4329: TEST : COMMON : size changed
If the /4Ys compile option or $STRICT metacommand is used with
FORTRAN 5.0, or if the program is compiled with FORTRAN 4.x, the
error
F2323: TEST : COMMON : size changed
is generated when a NAMED common block's size is changed in a
subprogram.
Under Fortran PowerStation 4.0 using the /4Ys compile option or the
$STRICT metacommnad, a change in a subprogram common block's size
generates the following error message:
error FOR3750: byte count on numeric data type detected
between * and 4
Additional query words:
kbinf 1.00 4.00 5.00 5.10
Keywords : kbcode kbFortranPS kbLangFortran
Version : :1.0,1.0a,4.0,4.01,4.1,5.0,5.1
Platform : MS-DOS NT OS/2 WINDOWS
Issue type :
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