BUG: Access Violation or R6018 Executing IF Statement
ID: Q114979
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The information in this article applies to:
-
Microsoft FORTRAN PowerStation for MS-DOS, version 1.0a
-
Microsoft Fortran Powerstation 32 for Windows NT, version 1.0
SYMPTOMS
For FORTRAN PowerStation 32, an access violation occurs and for FORTRAN
PowerStation, runtime error R6018 and an unexpected heap error occur
when you execute code where:
- There is an IF statement alone (not "IF... THEN...").
.
- There is a call to a subroutine that takes a character argument in the
IF block.
- The actual argument passed to the subroutine is a character expression
that includes concatenation of characters.
- The IF expression is evaluated as ".FALSE" so that the call is not
carried out.
RESOLUTION
Use one of the following to work around the problem:
- Use a block IF (that is, "IF... THEN ...") rather than an IF statement
alone.
-or-
- Assign the character expression to a temporary variable instead of
passing it directly to the subroutine.
STATUS
Microsoft has confirmed this to be a bug in Microsoft FORTRAN
PowerStation, version 1.0a for MS-DOS and version 1.0 for Windows NT.
We are researching this problem and will post new information here
in the Microsoft Knowledge Base as it becomes available.
MORE INFORMATION
To reproduce the problem, compile and run the following sample code:
Sample Code
C compile options needed: none
CHARACTER*80 A
CHARACTER*3 end
LOGICAL L
end = 'End'
L = .FALSE.
C1 L = .TRUE.
A = 'This format bombs...'//end
C2 IF (L) print *, A
IF (L) print *, 'This format bombs...'//end
C3 IF (L) then
C3 print *, 'This format bombs...'//end
C3 end if
print *, end
END
To run the program without error:
- Uncomment C1.
-or-
- Comment out the single line "IF" and uncomment C2.
-or-
- Comment out the single line "IF" and uncomment C3.
Additional query words:
1.00 1.00a
Keywords :
Version : :1.0,1.0a
Platform :
Issue type :