ACC2000: Sample Function to Open a Form to a Particular Record
ID: Q210436
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The information in this article applies to:
Advanced: Requires expert coding, interoperability, and multiuser skills.
SUMMARY
This article shows you how to create a sample Visual Basic for Applications
function that uses the InputBox() function to open a form to a particular record.
MORE INFORMATION
The OpenFormWithInput() function opens the form to the record where the CustomerID matches the value that you enter in the input box.
If you change "=" to ">=" on the OpenForm line in the function, the form opens to the record that you want and displays subsequent records as well. For example, if you type CACTU as the CustomerID in the input box, CustomerID "AROUT" is not part of the form's record set, but "THEBI" is.
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- Open the sample database Northwind.mdb.
- Create a module and type the following line in the Declarations section if it is not already there:
Option Explicit
- Type the following procedure:
Function OpenFormWithInput()
Dim Msg As String
Dim Title As String
Dim Defvalue As String
Dim Answer As String
Msg = "Enter a Customer ID (AROUT, CACTU, THEBI, etc.)."
Title = "OPEN CUSTOMERS FORM"
Defvalue = "CACTU"
Answer = InputBox(Msg, Title, Defvalue)
If Answer <> "" Then
DoCmd.OpenForm "Customers", , , "[CustomerID]='" & Answer & "' "
Else
DoCmd.OpenForm "Customers"
End If
End Function
- Open the Customers form in Design view.
- Add a command button to the form, and set the OnClick property as follows:
=OpenFormWithInput()
- Open the form in Form view and click the command button. Accept the default value in the input box (or type any valid CustomerID) and click OK. Note that the form opens to the designated customer.
NOTE: If you type an invalid CustomerID in the input box, Microsoft Access displays a blank form.
Additional query words:
inf
Keywords : kbprg kbdta AccCon FmsHowto KbVBA
Version : WINDOWS:2000
Platform : WINDOWS
Issue type : kbhowto