ACC: New SQL Records Appear Deleted Until Recordset Reopened

ID: Q135379

The information in this article applies to:

Microsoft Access versions 7.0, 97

SYMPTOMS

Advanced: Requires expert coding, interoperability, and multiuser skills.

When you add a record to an SQL table by using Visual Basic for Applications, if the table's unique index field has a default value, and you do not assign a value to that field, the new record appears deleted until you reopen the SQL table. If you try to obtain a value from the new record, you receive the following error message:

Run-time error '3167'
Record is deleted.

RESOLUTION

When you open the SQL table by using Visual Basic code, include the dbSeeChanges option, as in the following example:


   Set rs = db.OpenRecordset("TestTable", dbOpenDynaset, dbSeeChanges)

The dbSeeChanges option ensures that any newly added records that contain a default value in the unique index field are available in the current recordset.

STATUS

This behavior is by design.

MORE INFORMATION

Steps to Reproduce Behavior

Create a module and type the following line in the Declarations section if it is not already there:
```
      Option Explicit 
```

Type the following procedure:


      Function TestSQLData()

         Dim db As Database, rs As Recordset
         Dim idx, td
         Dim cmd As String

         ' Delete TestTable if it exists on the SQL server.
         Set db = OpenDatabase("", False, False,ODBC;dsn=<datasource>; _
            database=<database>;uid=<user id>;pwd=<password>")
         cmd = "if exists (select * from sysobjects where _
            id = object_id('dbo.TestTable'))"
         cmd = cmd & " drop table TestTable"
         db.Execute cmd, dbSQLPassThrough

         ' Create TestTable with one field on SQL server.
         Set td = db.CreateTableDef("TestTable")
         td.Fields.Append td.CreateField("Int", dbInteger)
         td.Fields.Append td.CreateField("String", dbText, 50)
         db.TableDefs.Append td

         Set idx = td.CreateIndex("MyIdx")
         idx.Unique = True
         idx.Fields.Append idx.CreateField("Int")
         td.Indexes.Append idx

         cmd = "create Default TestDef3 as 100"
         db.Execute cmd, dbSQLPassThrough

         cmd = "sp_bindefault TestDef3, 'TestTable.Int'"
         db.Execute cmd, dbSQLPassThrough

         ' Open table, add a record, and then obtain values.
         Set rs = db.OpenRecordset("TestTable")
         rs.AddNew
         rs!String = "Trial"
         rs.Update

         Debug.Print "RecordCount = " & rs.RecordCount
         rs.MoveFirst
         Debug.Print "String is " & rs("String")
         Debug.Print "Int is " & rs("Int")
         rs.Close

      End Function

To test this function, type the following line in the Debug window, and then press ENTER:

? TestSQLData()

Note that run-time error '3167' occurs.

REFERENCES

For more information about the OpenRecordset method, search the Help Index for "OpenRecordset," and then "OpenRecordset method," or ask the Microsoft Access 97 Office Assistant.

Keywords : kberrmsg kbusage OdbcProb
Version : 7.0 97
Platform : WINDOWS
Issue type : kbprb