HOWTO: Arrange Order of List Items within ListBox Control
ID: Q167746
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The information in this article applies to:
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Microsoft Visual Basic Enterprise Edition for Windows, versions 5.0, 6.0
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Microsoft Visual Basic Professional and Enterprise Editions, 16-bit and 32-bit, for Windows, version 4.0
SUMMARY
This article contains sample code that illustrates how to arrange the order
of items within ListBox Control using drag-and-drop. Function ListRowCalc()
returns the list index by calculating the position using the Windows API
SendMessage() function with the constant LB_GETITEMHEIGHT and
Screen.TwipsPerPixelY. Sub ListRowMove inserts the dragged item into the
dropped position and re-orders all other affected items.
MORE INFORMATIONStep-by-Step Example
- Start a new project in Visual Basic. Form1 is created by default.
- Add a module to the project. The default is Module1.
- Paste the following code into the General Declarations section of
Module1:
#If Win16 Then
Declare Function SendMessage& Lib "User" (ByVal hWnd%, ByVal _
wMsg%, ByVal wParam%, lParam As Any)
#Else
Declare Function SendMessage Lib "user32" Alias "SendMessageA" _
(ByVal hWnd As Long, ByVal wMsg As Long, _
ByVal wParam As Long, lParam As Long) As Long
#End If
Function ListRowCalc(lstTemp As Control, ByVal Y As Single) As Integer
#If Win16 Then
Const WM_USER = &H400
Const LB_GETITEMHEIGHT = (WM_USER + 34)
#Else
Const LB_GETITEMHEIGHT = &H1A1
'Determines the height of each item in ListBox control in pixels
#End If
Dim ItemHeight As Integer
ItemHeight = SendMessage(lstTemp.hWnd, LB_GETITEMHEIGHT, 0, 0)
ListRowCalc = min(((Y / Screen.TwipsPerPixelY)\ItemHeight)+ _
lstTemp.TopIndex, lstTemp.ListCount - 1)
End Function
Function min(X As Integer, Y As Integer) As Integer
If X > Y Then min = Y Else min = X
End Function
Sub ListRowMove(lstTemp As Control, ByVal OldRow As Integer, _
ByVal NewRow As Integer)
Dim SaveList As String, i As Integer
If OldRow = NewRow Then Exit Sub
SaveList = lstTemp.List(OldRow)
If OldRow > NewRow Then
For i = OldRow To NewRow + 1 Step -1
lstTemp.List(i) = lstTemp.List(i - 1)
Next i
Else
For i = OldRow To NewRow - 1
lstTemp.List(i) = lstTemp.List(i + 1)
Next i
End If
lstTemp.List(NewRow) = SaveList
End Sub
- Add a ListBox Control (List1) to Form1.
- Clear all the code for Form1, and then paste the following code into the
General Declarations section of Form1:
Dim DragIndex As Integer
Private Sub Form_Load()
List1.Clear
List1.AddItem "Adam"
List1.AddItem "Bob"
List1.AddItem "Charles"
List1.AddItem "David"
List1.AddItem "Eric"
List1.AddItem "Frank"
List1.AddItem "George"
End Sub
Private Sub List1_DragDrop(Source As Control, X As Single, Y As Single)
ListRowMove Source, DragIndex, ListRowCalc(Source, Y)
End Sub
Private Sub List1_MouseDown(Button As Integer, Shift As Integer, _
X As Single, Y As Single)
If Button = vbRightButton Then
DragIndex = ListRowCalc(List1, Y)
List1.Drag
End If
End Sub
- Assign an icon file to the DragIcon property of List1. Icon files are
shipped with Visual Basic 4.0 under \ICONS directory.
- From the Run menu, choose Start to run the program. Drag-and-drop any
list item in List1 using the right-mouse button. The order of list
items should be re-arranged accordingly.
REFERENCES
For additional information on how to drag-and-drop onto a list box, please
see the following articles in the Microsoft Knowledge Base:
Q80187
: HOWTO: Drop Item into Specified Location in VB List Box
(c) Microsoft Corporation 1997, All Rights Reserved.
Contributions by Adrian Chiang, Microsoft Corporation.
Additional query words:
kbVBp500 kbVBp600 kbdse kbDSupport kbVBp kbVBp400
Keywords : kbGrpVBDB
Version :
Platform : WINDOWS
Issue type : kbhowto
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