BUG: Incorrect Code When Increment Pointer Based on a Pointer
ID: Q122543
|
The information in this article applies to:
-
The C/C++ Compiler (CL.EXE), included with:
-
Microsoft C/C++ for MS-DOS
-
Microsoft Visual C++ for Windows
-
Microsoft Visual C++ 32-bit Edition, versions 1.0, 2.0, 2.1, 4.0, 4.1, 5.0
-
Microsoft Visual C++, 32-bit Editions, version 6.0
SYMPTOMS
Incorrect code is generated when an assignment is made in the same
statement where a pointer based on a pointer is incremented.
For example, executing the following code:
char buf[100];
void *pvbuf=buf;
unsigned int _based(pvbuf) *Test;
*(char _based(pvbuf) *)(((char *)Test)++) = '6'
in a Win32-based application causes an application error; executing the
same code in a 16-bit Windows-based application causes this error:
run-time error R6001
-null pointer assignment
CAUSE
The compiler generates an unnecessary sub command, as shown here:
mov bx,WORD PTR _Test
sub bx,WORD PTR _pvbuf ; Not needed
mov si,WORD PTR _pvbuf
mov BYTE PTR [bx][si],5
inc WORD PTR _Test
RESOLUTION
Split the statement into multiple lines. For example,
*(char _based(pvbuf) *)(((char *)Test)) = '5';
((char*)Test)++;
STATUS
Microsoft has confirmed this to be a bug in the Microsoft products listed
at the beginning of this article.
MORE INFORMATION
The following sample demonstrates both the problem and its solution.
Sample Code
/* Compile options needed: none
*/
#include <stdio.h>
#include <conio.h>
char buf[100];
void *pvbuf=buf;
unsigned int _based(pvbuf) *Test;
void good()
{
*(char _based(pvbuf) *)(((char *)Test)) = '5';
((char*)Test)++;
*(char _based(pvbuf) *)(((char *)Test)) = '5';
}
void bad()
{
*(char _based(pvbuf) *)(((char *)Test)++) = 6;
}
void main(void)
{
good();
printf( "Should print out: 5 5 \n%c %c\n",buf[0],buf[1] );
getch();
bad();
printf( "Should print out: 5 6 \n%c %c\n",buf[0],buf[1] );
}
Additional query words:
kbVC400bug 8.00 8.00c 9.00 10.00 10.10 10.20
Keywords : kbCodeGen kbVC500bug
Version : winnt:6.0
Platform : winnt
Issue type : kbbug