HOWTO: Convert 10-Byte Long Doubles to 8-Byte Doubles
ID: Q129209
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The information in this article applies to:
-
Microsoft C/C++ Compiler (CL.EXE), included with:
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Microsoft Visual C++, 32-bit Editions, versions 1.0, 2.0, 2.1, 4.0, 5.0
on the following platforms: x86
SUMMARY
With the 16-bit Microsoft C/C++ compilers, long doubles are stored as 80-
bit (10-byte) data types. Under Windows NT, in order to be compatible with
other non-Intel floating point implementations, the 80-bit long double
format is aliased to the 64-bit (8-byte) double format.
This means that 32-bit programs may not be able read back data files
written by 16-bit programs because the long double formats are
incompatible.
On Intel platforms, the only workaround is to let the floating point
processor handle the conversion from 80-bit to 64-bit doubles. Afterwards,
the data can be stored back into a 64-bit double for use under Win32.
The sample code below illustrates how you could use floating point
instructions in inline assembly to convert from a 10-byte double in a data
file to an 8-byte double.
Sample Code
/* Compile options needed: none
*/
#include <stdio.h>
void main(void)
{
FILE *inFile;
char buffer[10];
long double Newdbl;
inFile = fopen("data","rb");
fread(buffer, 10, 1, inFile); // reads in 10-byte long double
fclose(inFile);
// This moves the contents of the buffer into the floating point
// register, which then then takes care of the automatic convertion
// back to a 8-byte long double
_asm {
fld TBYTE PTR buffer;
fstp Newdbl;
}
}
Additional query words:
8.00 9.00 9.10
Keywords : kbCompiler kbVC100 kbVC200 kbVC210 kbVC400 kbVC500 kbVC600
Version :
Platform : WINDOWS winnt
Issue type : kbhowto