This function determines the number of intervals between two dates.
DateDiff(interval, date1, date2, [firstdayofweek], [firstweekofyear])
Setting |
Description |
yyyy | Year |
q | Quarter |
m | Month |
y | Day of year |
d | Day |
w | Weekday |
ww | Week of year |
h | Hour |
m | Minute |
s | Second |
Constant |
Value |
Description |
vbUseSystem | 0 | Use National Language Support (NLS) API setting |
vbSunday | 1 | Sunday (default) |
vbMonday | 2 | Monday |
vbTuesday | 3 | Tuesday |
vbWednesday | 4 | Wednesday |
vbThursday | 5 | Thursday |
vbFriday | 6 | Friday |
vbSaturday | 7 | Saturday |
Constant |
Value |
Description |
vbUseSystem | 0 | Use National Language Support (NLS) API setting. |
vbFirstJan1 | 1 | Start with the week in which January 1 occurs (default). |
vbFirstFourDays | 2 | Start with the week that has at least four days in the new year. |
vbFirstFullWeek | 3 | Start with the first full week of the new year. |
Returns the number of intervals between two dates.
Use DateDiff to determine how many specified time intervals exist between two dates. For example, you can use DateDiff to calculate the number of days between two dates or the number of weeks between today and the end of the year.
To calculate the number of days between date1 and date2, use either day of year (y) or day (d). When interval is weekday (w), DateDiff returns the number of weeks between the two dates. If date1 falls on a Monday, DateDiff counts the number of Mondays until date2. It counts date2 but not date1. However, if interval is week (ww), DateDiff returns the number of calendar weeks between the two dates. It counts the number of Sundays between date1 and date2. DateDiff counts date2 if it falls on a Sunday; but it does not count date1, even if it falls on a Sunday.
If date1 refers to a later point in time than date2, DateDiff returns a negative number.
The firstdayofweek parameter affects calculations that use the w and ww interval symbols.
If date1 or date2 is a date literal, the specified year becomes a permanent part of that date. However, if date1 or date2 is enclosed in quotation marks ("") and you omit the year, the current year is inserted in your code each time the date1 or date2 expression is evaluated. This makes it possible to write code that can be used in different years.
When comparing December 31 to January 1 of the succeeding year, DateDiff for Year (yyyy) returns 1 even though only a day has elapsed.