ANSI 3.5.2.1 The order of allocation of bit fields within an int
Bit fields are allocated within an integer from least-significant to most-significant bit. In the following code
struct mybitfields
{
unsigned a : 4;
unsigned b : 5;
unsigned c : 7;
} test;
void main( void )
{
test.a = 2;
test.b = 31;
test.c = 0;
}
the bits would be arranged as follows:
00000001 11110010
cccccccb bbbbaaaa
Since the 80x86 processors store the low byte of integer values before the high byte, the integer 0x01F2 above would be stored in physical memory as 0xF2 followed by 0x01.